Rd | 287 | J / (kg.K) |
---|---|---|
Rv | 462 | J / (kg.K) |
specific heat | cp | 1010 | J / (kg . K) |
---|---|---|---|
Ltnt heat vap | Lv | 2.5e6 | J / kg |
eS(T) = 6.112 exp [ 17.67 T / (243.5+T) ]
T(e) = 243.5 / [ 17.67 / ln(e / 6.112) - 1 ]
where e is to be inserted in millibars, and T will be in degrees Celcius. When using this formula, you might want to check at least once against the table given below, just to be sure you are doing the operations in the correct order. Note that ln( ) denotes the natural logarithm.
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